4c^2+12c+5=0

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Solution for 4c^2+12c+5=0 equation:


Simplifying
4c2 + 12c + 5 = 0

Reorder the terms:
5 + 12c + 4c2 = 0

Solving
5 + 12c + 4c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(5 + 2c)(1 + 2c) = 0

Subproblem 1

Set the factor '(5 + 2c)' equal to zero and attempt to solve: Simplifying 5 + 2c = 0 Solving 5 + 2c = 0 Move all terms containing c to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + 2c = 0 + -5 Combine like terms: 5 + -5 = 0 0 + 2c = 0 + -5 2c = 0 + -5 Combine like terms: 0 + -5 = -5 2c = -5 Divide each side by '2'. c = -2.5 Simplifying c = -2.5

Subproblem 2

Set the factor '(1 + 2c)' equal to zero and attempt to solve: Simplifying 1 + 2c = 0 Solving 1 + 2c = 0 Move all terms containing c to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + 2c = 0 + -1 Combine like terms: 1 + -1 = 0 0 + 2c = 0 + -1 2c = 0 + -1 Combine like terms: 0 + -1 = -1 2c = -1 Divide each side by '2'. c = -0.5 Simplifying c = -0.5

Solution

c = {-2.5, -0.5}

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